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A chord 10 cm long is drawn in a circle whose radius is 5√2 cm. Find the area of both segments

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Given radius = r = 5√2 cm = OA = OB

Length of chord AB = 10cm

In ΔOAB, OA = OB = 5√2 AB = 10cm OA2+OB2=(5√2)2+(5√2)2=50+50=100=(AB)2

Pythagoras theorem is satisfied OAB is right triangle

= angle subtended by chord = ∠AOB = 90°

Area of segment (minor) = shaded region

= area of sector − area of ΔOAB

Area of major segment = (area of circle) – (area of minor segment)

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