Given radius = r = 5√2 cm = OA = OB

Length of chord AB = 10cm

In ΔOAB, OA = OB = 5√2 AB = 10cm OA^{2}+OB^{2}=(5√2)^{2}+(5√2)^{2}=50+50=100=(AB)^{2}

Pythagoras theorem is satisfied OAB is right triangle

= angle subtended by chord = ∠AOB = 90°

Area of segment (minor) = shaded region

= area of sector − area of ΔOAB

Area of major segment = (area of circle) – (area of minor segment)