Given radius = r = 5√2 cm = OA = OB
Length of chord AB = 10cm
In ΔOAB, OA = OB = 5√2 AB = 10cm OA2+OB2=(5√2)2+(5√2)2=50+50=100=(AB)2
Pythagoras theorem is satisfied OAB is right triangle
= angle subtended by chord = ∠AOB = 90°
Area of segment (minor) = shaded region
= area of sector − area of ΔOAB
Area of major segment = (area of circle) – (area of minor segment)
