Let the breadth be x m. The length will be (2x + 2) m.
Perimeter of swimming pool = 2(l + b) = 154 m
2(2x + 2 + x) = 154
2(3x + 2) = 154
Dividing both sides by 2, we obtain
293X + 2/2 = 154/2
3x + 2 = 77
On transposing 2 to R.H.S, we obtain
3x = 77 − 2
3x = 75
On dividing both sides by 3, we obtain
x = 25
2x +2 = 2 x 25+2 = 52
Hence, the breadth and length of the pool are 25 m and 52 m respectively.
