Sarthaks Test
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The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/15 cm. What is the length of either of the remaining equal sides?

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Let the length of equal sides be x cm.

Perimeter = x cm + x cm + Base = 4 2/15 cm

2x + 4/3 = 62/15

On transposing 4/3 to R.H.S, we obtain

2x = 62/15 - 4/3

2x = 62 - 4 x 5/15 = 62 - 20/15

2x = 42/15

On dividing both sides by 2, we obtain

2x/2 = 42/15 x1/2

x = 7/5 = 1 2/5

Therefore, the length of equal sides is 1 2/5 c m.

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