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+2 votes
32.3k views
in Chemistry by (29.3k points)

The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is .... × 10–5 mol dm–3. (Round off to the Nearest Integer).

[Given : Henry's law constant = KH = 8.0 × 104 kPa for O2 .

Density of water with dissolved oxygen = 1.0 kg dm–3]

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2 Answers

+2 votes
by (30.3k points)

Means 1 mole water (= 18 gm = 18 ml) dissolves

\(\frac{1}{4000}\) moles O2. Hence, molar solubility

0 votes
by (35 points)

Here is the answer provided. thank you.

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