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Three consecutive integers add up to 51. What are these integers?

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Let three consecutive integers be x, x + 1, and x + 2. Sum of these numbers = x+ x + 1 + x + 2 = 51 

3x + 3 = 51

On transposing 3 to R.H.S, we obtain

3x = 51 − 3

3x = 48

On dividing both sides by 3, we obtain

3x/3 = 48/3

x = 16

x + 1 = 17

x + 2 = 18

Hence, the consecutive integers are 16, 17, and 18.

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