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The sum of three consecutive multiples of 8 is 888. Find the multiples.

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Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2). 

Sum of these numbers = 8x + 8(x + 1) + 8(x + 2) = 888 

8(x + x + 1 + x + 2) = 888

8(3x + 3) = 888

On dividing both sides by 8, we obtain

8( 3x + 3)/8 = 888/8

3x + 3 =  108

On transposing 3 to R.H.S, we obtain

3x = 111 − 3

3x = 108

On dividing both sides by 3, we obtain

3x/3 = 108/3

x = 36

First multiple = 8x = 8 × 36 = 288

Second multiple =8(x + 1) = 8 x (36 + 1) = 8 x 37 = 296

Third multiple = 8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304 

Hence, the required numbers are 288, 296, and 304.

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