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0 votes
14.9k views
in Chemistry by (29.3k points)
edited by

Consider the reaction N2O4 (g) {\displaystyle \rightleftharpoons \,}2NO2 (g).

The temperature at which KC = 20.4 and KP = 600.1, is ...... K. (Round off to the Nearest Integer).

[Assume all gases are ideal and R = 0.0831 L bar K–1 mol–1]

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1 Answer

+1 vote
by (30.3k points)

N2O4 (g) {\displaystyle \rightleftharpoons \,}2NO2 (g); Δng = 2 - 1 = 1

Now, Kp = Kc .(RT)Δng

or, 600.1 = 20.4 × (0.0831 × T)1

∴ T = 353.99 K = 354K

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