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in Commercial Mathematics by (55 points)
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Find the simple interest on 540000/= invested for 18 months at rate of 10% pa

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1 Answer

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P = Rs. 540000

R = 10%

T = 18 months = \(1 \frac{1}{2}\) = \(\frac{3}{2}\) years

S.I = \(\frac{P \times R \times T}{100}\)

\(\frac{540000 \times 10 \times 3}{100 \times 2}\)

= Rs.5400 x 5 x 3

= Rs.81000

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