Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Number System by (36.4k points)
closed by

Find the multiplicative inverse (reciprocal) of each of the following rational numbers:

(i) 9

(ii) -7

(iii) \(\frac{12}{5}\)

(iv) \(\frac{-7}{9}\)

(v) \(\frac{-3}{-5}\)

(vi) \(\frac{2}{3}\times \frac{9}{4}\)

(vii) \(\frac{-5}{8}\times \frac{16}{15}\)

(viii) \(-2\times \frac{-3}{5}\)

(ix) -1

(x) \(\frac{0}{3}\)

(xi)1

1 Answer

+1 vote
by (38.0k points)
selected by
 
Best answer

(i) Reciprocal of 9 is \(\frac{1}{9}\)

(ii) Reciprocal of –7 is \(\frac{-1}{7}\)

(iii) Reciprocal of \(\frac{12}{5}\) is \(\frac{5}{12}\)

(iv) Reciprocal of \(\frac{-7}{9}\) is \(\frac{9}{-7}\)

(v) Reciprocal of \(\frac{-3}{-5}\) is \(\frac{5}{3}\)

(vi) \(\frac{2}{3}\times \frac{9}{4}\) = \(\frac{3}{2}\)

Reciprocal of \(\frac{3}{2}\) is \(\frac{2}{3}\)

(vii) \(\frac{-5}{8}\times \frac{16}{15}\) = \(\frac{-2}{3}\)

Reciprocal of \(\frac{-2}{3}\) is \(\frac{3}{-2}\)

(viii) \(-2\times \frac{-3}{5}\)\(\frac{6}{5}\)

Reciprocal of \(\frac{6}{5}\) is \(\frac{5}{6}\)

(ix) Reciprocal of -1 is -1

(x) Reciprocal of \(\frac{0}{3}\) is not defined as in the form of \(\frac{p}{q}\) , q = 0, so it is not a rational number

(xi) Reciprocal of 1 is 1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...