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If a= 2i-3j+k,b=-i+k and c=2j-k. Find the area of parallelogram whose diagonals are a+b and b+c

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D1 = a + b = i - 3j + 2k

D2 = b + c = -i + 2j

Area of parallelogram = 1/2 |Dx D2|
=>  1/2 |(i - 3j + 2k) x (-i + 2j)|
=>  1/2|-4i - 2j - k|
=> √21 / 2

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