2x/3 + 1 = 7x/15 + 3

Transposing 7x/15 to L.H.S and 1 to R.H.S, we obtain

2x/3 - 7x/15 = 3 -1

5 x 2x- 7x/15 = 2

3x/15 = 2

x/5 = 2

Multiplying both sides by 5, we obtain

x = 10

L.H.S = 2x/3 +1 = 2 x 10/3 + 1

= 2 x 10+ 1 x 3/3 = 23/3

R.H.S = 7x/15 + 3 = 7 x 10/15 + 3 = 7 x2/3 + 3

= 14 + 3 x 3/3 = 23/3

L.H.S. = R.H.S.

Hence, the result obtained above is correct.