If the Boolean expression (p ⇒ q) ⇔ (q * (~p)) is a tautology, then the Boolean expression p * (~q)

Question

If the Boolean expression \((p \Rightarrow q)\Leftrightarrow (q\, *(\sim p))\) is a tautology, then the Boolean expression \(p\, *(\sim q)\) is equivalent to :

(1) \(q \Rightarrow p\)

(2) \(\sim q \Rightarrow p\)

(3) \(p \Rightarrow \sim q\)

(4) \(p \Rightarrow q\)

Answer 1

Correct answer is (1)