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0 votes
20.0k views
in Mathematics by (34.9k points)
edited by

Consider a hyperbola H : x2 – 2y2 = 4. Let the tangent at a point P(4, √6) meet the x-axis at Q and latus rectum at R(x1, y1), x1 > 0. If F is a focus of H which is nearer to the point P, then the area of △QFR is equal to

(1) 4√6

(2) √6 - 1

(3) \(\frac{7}{\sqrt6}\) - 2

(4) 4√6 - 1

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1 Answer

+3 votes
by (34.4k points)

Correct option is (3) \(\frac{7}{\sqrt6}-2\)

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