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–1 vote
31.8k views
in Mathematics by (31.4k points)

The sum of possible values of x for

\(tan^{-1}(x+1)+cot^{-1}\bigg(\frac{1}{x-1}\bigg)\) \(=tan^{-1}\bigg(\frac{8}{31}\bigg)\) is :

(1) \(-\frac{32}{4}\)

(2) \(-\frac{31}{4}\)

(3) \(-\frac{30}{4}\)

(4) \(-\frac{33}{4}\)

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1 Answer

+2 votes
by (30.9k points)

Correct answer is (1)

Taking tangent both sides :-

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