The L.C.M of denominators 5 and 4 is 20
Converting the given rational numbers into equivalent rational number having common denominator 20
we get:
\(\frac{3}{5}\times \frac{20}{20}\) = \(\frac{60}{100}\)
\(\frac{3}{4}\times \frac{25}{25}\) = \(\frac{75}{100}\)
Clearly,
61, 62, 63,…, 74 are integers between numerators 60 and 75 of these equivalent rational numbers
Thus we have
\(\frac{61}{100}\),\(\frac{62}{100}\),.......,\(\frac{74}{100}\)
As rational number between \(\frac{3}{5}\) and \(\frac{3}{4}\)
We can take only 10 of these as required rational numbers
\(\frac{61}{100}\),\(\frac{62}{100}\),\(\frac{63}{100}\),...........,\(\frac{73}{100}\),\(\frac{74}{100}\)
