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0 votes
22.8k views
in Mathematics by (35.0k points)

Define a relation R over a class of n × n real matrices A and B as "ARB if there exists a non-singular matrix P such that PAP–1 = B".

Then which of the following is true ?

(1) R is symmetric, transitive but not reflexive,

(2) R is reflexive, symmetric but not transitive 

(3) R is an equivalence relation

(4) R is reflexive, transitive but not symmetric

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1 Answer

+2 votes
by (34.5k points)

Correct option is (3) R is an equivalence relation

A and B are matrices of n × n order & ARB if there exists a non singular matrix P(det(P) ≠ 0) such that PAP–1 = B

For reflexive

ARA ⇒ PAP–1 = A ...(1) must be true for P = I, Eq.(1) is true so 'R' is reflexive

For symmetric

ARB ⇔ PAP–1 = B ...(1) is true

for BRA if PBP–1 = A ...(2) must be true

\(\because\) PAP–1 = B

P–1PAP–1 = P–1B

IAP–1P = P–1BP

A = P–1BP ...(3)

from (2) & (3) PBP–1 = P–1BP

can be true some P = P–1 ⇒ P2 = I (det(P) ≠ 0)

So 'R' is symmetric

For transitive

ARB ⇔ PAP–1 = B... is true

BRC ⇔ PBP–1 = C... is true

now PPAP–1P–1 = C

P2A(P2)–1 = C

⇒ ARC So 'R' is  transitive relation

⇒ Hence R is equivalence.

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