(i) \((\frac{3}{4})^{-2}\)
⇒ \((\frac{3}{4})^{-2}\)= \((\frac{4}{3})^{2}\)[Using \((\frac{a}{b})^{-n}\)= \((\frac{b}{a})^{n}\)]
(ii) \((\frac{5}{4})^{-3}\)
⇒ \((\frac{5}{4})^{-3}\)= \((\frac{4}{5})^{a}\)[Using \((\frac{a}{b})^{-n}\)= \((\frac{b}{a})^{n}\) ]
(iii) \(4^{3}\times 4^{-9}\)
⇒ \(4^{3}\times 4^{-9}\)= \(4^{3-9}\)= \(4^{-6}\)[Using (aⁿ× aᵐ = aᵐ⁺ⁿ ]
⇒ \(4^{-6}\)= \((\frac{1}{4})^{6}\)[Using \(\frac{1}{a^{n}}\)= \(a^{-n}\)]
(iv) \(\{(\frac{4}{3})^{-3}\}^{-4}\)
⇒ \(\{(\frac{4}{3})^{-3}\}^{-4}\)= \((\frac{4}{3})^{12}\)[Using (aⁿ)ᵐ = aᵐⁿ ]
(v) \(\{(\frac{3}{2})^{4}\}^{-2}\)
⇒ \(\{(\frac{3}{2})^{4}\}^{-2}\)= \((\frac{3}{2})^{-8}\)= \((\frac{2}{3})^{8}\)[Using (aⁿ)ᵐ = aᵐⁿ and \(\frac{1}{a^{n}}\)= \(a^{-n}\)]