Let the number of wheat and rice bags be x and y.
∴According to the question,
120x + 180y ≤ 1500, x + y ≤ 10,x ≥ 0, y ≥ 0
Maximize Z = 8x + 11y
The feasible region determined by 120x + 180y ≤ 1500, x + y ≤ 10,x ≥ 0, y ≥ 0 is given by
The corner points of feasible region are A(0,8), B(0,0), C(10,0), D(5,5) .
The value of Z at corner point is
The maximum value of Z is 95 at point (5,5).
Hence, the man should 5 bags each of wheat and rice to earn maximum profit.