Let the firm manufacture x number of A and y number of B products.
∴According to the question,
X + y ≤ 400, 2x + y ≤ 600, x ≥ 0,y ≥ 0
Maximize Z = 2x + 2y
The feasible region determined by X + y ≤ 400, 2x + y ≤ 600, x ≥ 0, y ≥ 0 is given by
The corner points of feasible region are A(0,0) , B(0,400) , C(200,200) , D(300,0).
The value of Z at corner point is
Corner Point |
Z = 2x + 2y |
|
A(0, 0) |
0 |
|
B(0, 400) |
800 |
Maximum |
C(200, 200) |
800 |
Maximum |
D(300, 0) |
600 |
|
The maximum value of Z is 800 and occurs at two points. Hence the line BC is a feasible solution.
The firm should produce 200 number of A products and 200 number of B products.