Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
728 views
in Algebraic Expressions by (38.0k points)
closed by

Simplify each of the following:

(i) \(x^{2}-3x+5-\frac{1}{2}(3x^{2}-5x+7)\)

(ii) \([5-3x+2y-(2x-y)]-(3x-7y+9)\)

(iii) \(\frac{11}{2}x^{2}y-\frac{9}{4}xy^{2}+\frac{1}{4}xy-\frac{1}{14}y^{2}x+\frac{1}{15}yx^{2}+\frac{1}{2}xy\)

(iv) \((\frac{1}{3}y^{2}-\frac{4}{7}y+11)-(\frac{1}{7}y-3+2y^{2})-(\frac{2}{7}y-\frac{2}{3}y^{2}+2)\)

(v) \(-\frac{1}{2}a^{2}b^{2}c^{2}+\frac{1}{3}ab^{2}c-\frac{1}{4}abc^{2}-\frac{1}{5}cb^{2}a^{2}+\frac{1}{6}cb^{2}a-\frac{1}{7}c^{2}ab+\frac{1}{8}ca^{2}b\)

1 Answer

+1 vote
by (36.4k points)
selected by
 
Best answer

(i) \(x^{2}-3x+5-\frac{1}{2}(3x^{2}-5x+7)\)

 (ii) \([5-3x+2y-(2x-y)]-(3x-7y+9)\)

= 5 – 3x + 2y – 2x + y – 3x + 7y – 9

= - 8x + 10y – 4

 (iii) \(\frac{11}{2}x^{2}y-\frac{9}{4}xy^{2}+\frac{1}{4}xy-\frac{1}{14}y^{2}x+\frac{1}{15}yx^{2}+\frac{1}{2}xy\)

 (iv) \((\frac{1}{3}y^{2}-\frac{4}{7}y+11)-(\frac{1}{7}y-3+2y^{2})-(\frac{2}{7}y-\frac{2}{3}y^{2}+2)\)

 (v) \(-\frac{1}{2}a^{2}b^{2}c^{2}+\frac{1}{3}ab^{2}c-\frac{1}{4}abc^{2}-\frac{1}{5}cb^{2}a^{2}+\frac{1}{6}cb^{2}a-\frac{1}{7}c^{2}ab+\frac{1}{8}ca^{2}b\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...