Let the invested money in bond A be x and in bond B be y.
∴According to the question,
X + y ≤ 12000, x ≥ 2000, y ≥ 4000
Maximize Z = 0.08x + 0.10y
The feasible region determined by X + y ≤ 12000, x ≥ 2000, y ≥ 4000 is given by
The corner points of the feasible region are A(2000,4000) , B(2000,10000) and C(8000,4000) .
The value of Z at the corner point are
Corner Point |
Z = 0.08x + 0.10y |
|
A(2000, 4000) |
560 |
|
B(2000, 10000) |
1160 |
Maximum |
C(8000, 4000) |
1040 |
|
The maximum value of Z is 116770 at point (2000,10000)
So, he must invest Rs.2000 in bond A and Rs.10000 in bond B.
The maximum annual income is Rs.1160 .