Let the company make x no of 1st kind and y no of 2nd cakes.
∴According to the question,
200x + 100y ≤ 5000, 25x + 50y ≤ 1000, x ≥ 0, y ≥ 0
Maximize Z = x + y
The feasible region determined by 200x + 100y ≤ 5000, 25x + 50y ≤ 1000, x ≥ 0, y ≥ 0 is given by
The corner points of feasible region are A(0,0) , B(0,20) , C(20,10) , D(25,0).
The value of Z at corner point is
Corner Point |
Z = x + y |
|
A(0, 0) |
0 |
|
B(0, 20) |
20 |
|
C(20, 10) |
30 |
Maximum |
D(25, 0) |
25 |
|
The maximum value of Z is 30 and occurs at point (20,10).
The company should make 20 of 1st type and 10 of 2nd type.