Sarthaks Test
0 votes
1.8k views
in Mathematics by (7.9k points)

An iron spherical ball has been melted and recast into smaller balls of equal size. If the radius of each of the smaller balls is 1/4 of the radius of the original ball, how many such balls are made? Compare the surface area, of all the smaller balls combined together with that of the original ball.

1 Answer

0 votes
by (13.1k points)
selected by
 
Best answer

Given that radius of each of smaller ball = 1/4 Radius of original ball.

Let radius of smaller ball be r. 

Radius of bigger ball be 4r

Curved surface area of sphere = 4r2

Surface area of big ball (S1) = 4π(4r)2     ....…(3)

Surface area of each small ball  (S2) = 4πr2

Total surface area of 64 small balls

Therefore, Total surface area of small balls is equal to 4 times surface area of big ball.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...