x2 + \(\frac{1}{x\times x}\) = 18
Adding 2 on both sides, we get
x2 + \(\frac{1}{x\times x}\) + 2 = 18 + 2
x2 + \(\frac{1}{x\times x}\) + 2 × x × \(\frac{1}{x}\) = 20
(x + \(\frac{1}{x}\) )2 = 20
x + \(\frac{1}{x}\) = \(2\sqrt{5}\)
Given that,
x2 + \(\frac{1}{x\times x}\) = 18
Subtracting 2 from both sides, we get
x2 +\(\frac{1}{x\times x}\) - 2 × x × \(\frac{1}{x}\) = 18 – 2
(x - \(\frac{1}{x}\))2 = 16
x - \(\frac{1}{x}\) = 4