(i) \(\sqrt[3]{4^3\times6^3}\)
We have,
= \(\sqrt[3]{4^3\times6^3}\)
= \(\sqrt[3]{4^3}\times\) \(\sqrt[3]{6^3}\)
= \(4\times6\)
= 24.
(ii) \(\sqrt[3]{8\times17\times17\times17}\)
We have,
= \(\sqrt[3]{8\times17\times17\times17}\)
= \(\sqrt[3]{8\times}\) \(\sqrt[3]{17^3}\)
= \(\sqrt[3]{2^3}\times\) \(\sqrt[3]{17^3}\)
= \(2\times17 \)
= 34.
(iii) \(\sqrt[3]{700\times2\times49\times5}\)
We have,
= \(\sqrt[3]{700\times2\times49\times5}\)
Getting prime factors of numbers,
= \(\sqrt[3]{700\times2\times49\times5}\)
= \(\sqrt[3]{2\times2\times2\times5\times5\times7\times7\times5}\)
= \(\sqrt[3]{2^3\times5^3\times7^3}\)
= \(\sqrt[3]{2^3}\times\)\(\sqrt[3]{5^3}\times\) \(\sqrt[3]{7^3}\)
= 2 × 5 × 7 = 70.
(iv) \(125\sqrt[3]{a^3}\) - \(\sqrt[3]{125a^6}\)
We have,
= \(125\sqrt[3]{a^6}\) - \(\sqrt[3]{125a^6}\)
= \(125\sqrt[3]{(a^2) ^3}\) - \(\sqrt[3]{5^3(a^2)^3}\)
= \(125a^2\) - \(\sqrt[3]{5^3(a^2)^3}\)
= \(125a^2\) - \(\sqrt[3]{5^3}\times\sqrt[3]{(a^2)^3}\)
= \(125a^2\) - \(5a^2\)
= \(120a^2. \)