As the pair of die is thrown 4 times,
The total number of outcomes = 36
Using Bernoulli’s Trial P(Success=x) \(=n_{C_x}.p^x.q^{(n-x)}\)
x = 0, 1, 2, ………n and q = (1 - p)
The probability of success = p = \(\frac{6}{36}\) = \(\frac{1}{6}\)
q = \(\frac{5}{6}\)
probability of 2 successes = \(4_{C_2}.(\frac{1}{6})^2(\frac{5}{6})^2\)
\(\Rightarrow\) \(\frac{25}{216}\)