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There are 6% defective items in a large bulk of times. Find the probability that a sample of 8 items will include not more than one detective item.

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Using Bernoulli’s Trial P(Success=x) \(=n_{C_x}.p^x.q^{(n-x)}\)

x = 0, 1, 2, ………n and q = (1 - p), n = 8

The probability of success, i.e. the bulb is defective \(=p=\frac{6}{100}=\frac{6}{100}\) \(q=1-\frac{6}{100}=\frac{94}{100}\)

probability of that there is not more than one defective piece =

P(0 defective items) + P(1 defective item) =

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