(i) \(\sqrt[3]{125\times27} = 3 \times......\)
We have,
= \(\sqrt[3]{125\times27}\)
= \(\sqrt[3]{5\times5\times5\times3\times3\times3}\)
Hence,
(ii) \(\sqrt[3]{8\times......} = 8\)
Hence,
(iii) \(\sqrt[3]{1728} = 4\times .......\)
We have,
= 4 x 3
Hence,
\(\sqrt[3]{1728} = 4\times3\)
(iv) \(\sqrt[3]{480} = \) \(\sqrt[3]{3\times2\times\times}\) \(\sqrt[3]{....}\)
We have,
Hence,