Question

The standard Gibbs energy change for a gaseous reaction at 27 is X Kcal. If equilibrium constant a reaction is 100 and R is 2 cal K⁻¹ mol⁻¹. Then X is:

Answer 1

ΔG^o=−RT lnK

∴X = −2 × 300 × ln 100

∴ X = −2.7636 K cal