Correct Answer is (B) [-1, 1]
Given: \(f(x)=\frac{sin^{-1}x}{x}\)
From f(x), x ≠ 0
Now, domain of sin-1x is [-1, 1] as the values of sin-1x lies between -1 and 1.
We can see that from this graph:
Domain of f(x) = [-1, 1] – 0
Hence, B is the correct answer.