Lest assume the numbers be 2a, 3a, and 4a.
According to the question:
(2a)3+ (3a)3+(4a)3 = 0.334125
= 8a3+27 a3+64 a3 = 0.334125
=99 a3 = 0.334125
= a3 = \(\frac{334125}{1000000\times99} = \frac{3375}{1000000}\)
= a = \(\frac{\sqrt[3]{3375}}{1000000}\)
= a = \(\frac{\sqrt[3]{3375}}{\sqrt[3]{1000000}}\)
= a = \(\frac{15}{100} = 0.15\)
Thus the numbers are:
2×0.15 = 0.30
3×0.15 = 0.45
4×0.15 = 0.60