Correct answer is C.
P(A) = \(\frac{1}{4},\) P(B) = \(\frac{1}{3}\) and P(A ∩ B) = \(\frac{1}{5},\)
\(P(\overline{B}/\overline{A})\) = \(\frac{P(\overline{A}\cap \overline{B})}{P(\overline{A})}\) = \(\frac{1-p(A \cup B)}{1-p(A)}\) = \(\frac{1-(\frac{1}{4}+\frac{1}{3}-\frac{1}{5})}{1-\frac{1}{4}}\)