8 coins are tossed simultaneously. The probability of getting at least 6 heads is A. 7/64

Question

8 coins are tossed simultaneously. The probability of getting at least 6 heads is

A. \(\frac{7}{64}\)

B. \(\frac{57}{64}\)

C. \(\frac{37}{256}\)

D. \(\frac{249}{254}\)

Answer 1

Using Bernoulli’s Trial P(Success=x) = \(n_{C_x}.p^x.q^{(n-x)}\)

x = 0, 1, 2, ………n and q = (1 - p)

As the coin is tossed 8 times the total number of outcomes will be 2⁸.

And we know that the favourable outcomes of getting at least 6 heads are,successes will be, getting a head,

The probability of success is \(\frac{1}{2}\) and of failure is also \(\frac{1}{2}\)

the probability of getting at least 6 heads is = P(6) +P(7) +P(8)