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Let \(A=\begin{bmatrix}3&2\\7&5\end{bmatrix}\) and \(B=\begin{bmatrix}6&7\\8&9\end{bmatrix}\). Find (AB) –1.

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\(A=\begin{bmatrix}3&2\\7&5\end{bmatrix}\)

|A| = 15 – 14 = 1

adj \(A=\begin{bmatrix}5&-2\\-7&3\end{bmatrix}\)

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