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Given \(A=\begin{bmatrix}2&-3\\-4&7\end{bmatrix}\), compute A–1 and show that 2A–1 = 9I – A.

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\(A=\begin{bmatrix}2&-3\\-4&7\end{bmatrix}\)

|A| = 14 – 12 = 2 adj \(A=\begin{bmatrix}7&3\\4&2\end{bmatrix}\)

Hence, 2A –1 = 9I – A

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