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Show that \(A=\begin{bmatrix}-8&5\\2&4\end{bmatrix}\)satisfies the equation A2 + 4A – 42I = O. Hence, 

find A–1.

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\(A=\begin{bmatrix}-8&5\\2&4\end{bmatrix}\)

A2\(\begin{bmatrix}-8&5\\2&4\end{bmatrix}\)\(\begin{bmatrix}-8&5\\2&4\end{bmatrix}\) =\(\begin{bmatrix}64+10&-40+20\\-16+8&10+16\end{bmatrix}\)

\(=\begin{bmatrix}74&-20\\-8&26\end{bmatrix}\)

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