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+1 vote
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If \(A=\begin{bmatrix}3&1\\-1&2\end{bmatrix}\), show that A2 – 5A + 7I = O. 

Hence, find A –1.

1 Answer

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Best answer

\(A=\begin{bmatrix}3&1\\-1&2\end{bmatrix}\)

A2 =\(\begin{bmatrix}3&1\\-1&2\end{bmatrix}\)\(\begin{bmatrix}3&1\\-1&2\end{bmatrix}\)\(=\begin{bmatrix}9-1&3+2\\-3-2&-1+4\end{bmatrix}\)

\(=\begin{bmatrix}8&5\\-5&3\end{bmatrix}\)

Now, A2 – 5A + 7I\(=\begin{bmatrix}8&5\\-5&3\end{bmatrix}\)\(-5\begin{bmatrix}3&1\\-1&2\end{bmatrix}\)\(+7\begin{bmatrix}1&0\\0&1\end{bmatrix}\)

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