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Write the value of tan^-1{tan(15π/4)}.

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Write the value of tan-1{tan(\(\frac{15\pi}4\))}.

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Given tan-1 {tan (15π/4)}

= tan-1 {tan (4π - π/4)}

We know that tan (2π – θ) = -tan θ

= tan-1 (-tan π/4)

= tan-1 (-1)

= -π/4

∴ tan-1 {tan (15π/4)} = -π/4

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