Given : A die is tossed twice and ‘Getting an odd number on a toss’ is considered a success.
To find : probability distribution of the number of successes and mean (μ) and variance (σ2)
Formula used :
When a die is tossed twice,
Total possible outcomes =
‘Getting an odd number on a toss’ is considered a success.
P(0) = \(\frac{9}{36}=\frac{1}{4}\) (zero odd numbers = 9)
P(1) = \(\frac{18}{36}=\frac{1}{2}\) (one odd number = 18)
P(2) = \(\frac{9}{36}=\frac{1}{4}\) (two odd numbers = 9)
The probability distribution table is as follows,
The probability distribution table is as follows,
Mean = 1
Variance = 0.5