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Show that the matrix, \(A=\begin{bmatrix}1&0&-1\\-2&-1&2\\3&4&1\end{bmatrix}\)satisfies the equation, A3 – A2 – 3A – I3 = O. 

Hence, find A–1.

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\(A=\begin{bmatrix}1&0&-1\\-2&-1&2\\3&4&1\end{bmatrix}\)

A3 = A2.A

Thus, A3 – A2 – 3A – I

Now, (AAA) A–1. – (A.A) A–1 – 3.A A–1 – I.A–1 = 0

AA(A –1A) – A(A–1A) – 3(A–1A) = – 1(A–1I)

A2 – A – 3A – I = 0

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