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If \(A=\begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}\)

show that A–1 = A3.

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Best answer

\(A=\begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}\)

|A| = 3 + 6 – 8 = 1

Cofactors of A are:

C11 = 1 C21 = – 1 C31 = 0

C12 = – 2 C22 = 3 C32 = – 4

C13 = – 2 C23 = 3 C33 = – 3

Hence, A–1 = A3

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