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If \(A=\begin{bmatrix}1&2&2\\2&1&2\\1&2&1\end{bmatrix}\), find A–1 and prove that A2 – 4A–5I = O.

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Also, A2 – 4A – 5I = 0

Now, 6(A.A) A–1 – 4.A A–1 – 5I.A–1 = 0

= A – 4I – 5A–1 = 0

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