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Resolve each of the following quadratic trinomials into factors:

14x2 + 11xy - 15y2

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Here, coefficient of x2 = 14, coefficient of x = 11y and constant term = - 15y2

We shall now split up the coefficient of middle term i.e., 11y into two parts whose sum is 11y and product is 14 (-15y2) = - 210y2

Clearly,

21y – 10y = 11y and

(21y) (-10y) = - 210y2

So, we replace middle term 11xy = 21xy – 10xy

Thus, we have

14x2 + 11xy- 15y2 = 14x2 + 21xy - 10xy - 15y2

= 2x (7x – 5y) + 3y (7x – 5y)

= (2x + 3y) (7x - 5y)

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