Divide: y^4 - 3y^3 + 1/2 y^2 by 3y

Question

Divide:

y⁴ - 3y³ + \(\frac{1}{2}\)y² by 3y

Answer 1

\(\frac{y^4-3y^3+\frac{1y^2}{2}}{3y}\)= \(\frac{y^4}{3y}-\frac{3y^3}{3y}+\frac{y^2}{6y}\) = \(\frac{y^3}{3}-y^2+\frac{y}{6}\) [Using aⁿ÷a^m = a^n-m]