Divide: √3​ a^4 + 2√3a^3 + 3^2 - 6a by 3a ​

Question

Divide:

\(\sqrt{3}\)a⁴ + 2\(\sqrt{3}\)a³ + 3² - 6a by 3a

Answer 1

\(\frac{\sqrt{3}a^4}{3a}+\frac{2\sqrt{3}a^3}{3a}+\frac{9}{3a}-\frac{6a}{3a}\) = \(\frac{\sqrt{3}a^3}{3}+\frac{2\sqrt{3}a^2}{3}+\frac{3}{a}-2\) [Using aⁿ÷a^m = a^n-m]