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in Science by (15 points)
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1 Answer

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by (15 points)

In loop 1:

applying Kirchhoff's loop law:

+12v - 4i1 - 3i=0

4i1+3i=12 ------1

in loop 2:

applying Kirchhoff's loop law:

-5v-2i+2i1+4i1=0

-2i +6i1=5 ------2

on solving 1 and 2

i=11/6

i1=13/8

current through 3 ohm resistor=11/6

current through 4 ohm resistor=13/8

current through 2 ohm resistor=5/24


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