Additive inverse of a number \(\frac{a}{b}\) is the number \(-\frac{a}{b}\) such that, \(\frac{a}{b}\) + \((\frac{-a}{b})= 0\)
Therefore,
(i) Additive inverse of \(\frac{a}{b}\) is \(-\frac{a}{b}\)
(ii) Additive inverse of \(\frac{23}{9}\) is \(\frac{-23}{9}\)
(iii) Additive inverse of -18 is 18
(iv) Additive inverse of \(\frac{-17}{8}\) is \(\frac{17}{8}\)
(v)
\(\frac{15}{-4}= \frac{15\times-1}{-4\times-1}= \frac{-15}{4}\)
Therefore,
Additive inverse of \(\frac{-15}{4}\)is \(\frac{15}{4}\)
(vi)
\(\frac{-16}{-5}= \frac{-16\times-1}{-5\times-1}= \frac{16}{5}\)
Additive inverse of \(\frac{16}{5}\) is \(\frac{-16}{5}\)
(vii) Additive inverse of \(\frac{-3}{11}\) is \(\frac{3}{11}\)
(viii) Additive inverse of 0 is 0
(ix)
\(\frac{19}{-6}= \frac{19\times-1}{-6\times-1}= \frac{-19}{6}\)
Therefore,
Additive inverse of \(\frac{-19}{6}\) is \(\frac{19}{6}\)
(x)
\(\frac{-8}{-6}= \frac{-8\times-1}{-7\times-1}= \frac{8}{7}\)
Additive inverse of \(\frac{8}{7}\) is \(\frac{-8}{7}\)