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Write the value of the determinant \(\begin{vmatrix} a & 1 & b+c \\ b & 1 & c+a \\ c & a & a+b \end{vmatrix}.\)

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Using the property that if the equimultiples of corresponding elements of other rows (or columns) are added to every element of any row (or column) of a determinant, then the value of determinant remains the same.

Using column transformation, C1→C1+C3

Using the property that if each element of a row (or a column) of a determinant is multiplied by a constant k, then its value gets multiplied by k.

Taking out factor(a + b + c) from C1,

We get,

Using column transformation, C1→C1-C2

We get,

Expanding along C1, we get

∆ = (a + b + c) × [(1 - a)(c + a - (b + c))]=(1 - a)(a - b)(a + b + c)

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