Given,
A pipe can fill a cistern in = 10 hours
Due to leakage it get filled in = 12 hours
∵ Without leakage work done by pipe in 1 hour \(=\frac{1}{10}\)part
∵ With leakage work done by pipe in 1 hour \(=\frac{1}{12}\)part
∴ Work done by leakage in 1 hour =\(\frac{1}{10}-\frac{1}{12}=\frac{12-10}{120}=\frac{2}{120}=\frac{1}{60}\)part
Hence, the cistern will be emptied by leakage in \(=\frac{1}{\frac{1}{60}}\)=60 hours.