Sarthaks Test
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Solve the following equations and also check your result in each case:

x - \(\frac{(x-1)}2\) = 1 - \(\frac{(x-2)}3\)

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 x - \(\frac{(x-1)}2\) = 1 - \(\frac{(x-2)}3\)

On transposing \(-\frac{x-2}3\) to LHS, we get

1 + \(\frac15\) = \(\frac65\)

We got LHS=RHS

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